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Home >> Subaru >> 2003 >> Impreza RS, Automatic >> Repair and Diagnosis >> Transmission >> Automatic Trans >> Overhaul >> Transfer Clutch >> Adjustment >> VTD Model

VTD Model

  1. Insert the rear drive shaft into the reduction drive gear and center differential assembly.
    Fig 1: Inserting Rear Drive Shaft Into Reduction Drive Gear & Center Differential Assembly
    G01998964Courtesy of SUBARU OF AMERICA, INC.
  2. Measure distance L from extension case mating surface to multi-plate clutch (LSD) piston with ST.

    ST 398643600 GAUGE

    L = Measured value - 15 mm

    (L = Measured value - 0.59 in)

    Fig 2: Measure Distance L
    G01998965Courtesy of SUBARU OF AMERICA, INC.

    A:  Measured value

    B:  ST thickness [15 mm (0.59 in)]

    L:  Distance from end of extension case to end of rear drive shaft

  3. Measure the distance "l" from the transmission case mating surface to the reduction drive gear end surface with ST.

    l  = Measured value - 15 mm

    (l  = Measured value - 0.59 in)

    ST 398643600 GAUGE

    Fig 3: Measure Distance "l" From Transmission Case Mating Surface To Reduction Drive Gear End Surface With ST
    G01998966Courtesy of SUBARU OF AMERICA, INC.

    A:  Measured value

    B:  ST thickness [15 mm (0.59 in)]

    l  : Distance from end of extension case to end of reduction drive gear

  4. Calculation equation:
    NOTE: Calculating H:
    When clearance is at 0.05 mm (0.0020 in) and 0.25 mm (0.0098 in), then select up to 4 shims from the table so that their total thickness matches the clearance.
    H = (L + 0.45 mm) - l  - T
    [H = (L + 0.0177 in) - l  - T]
    T:  Shim clearance
    L:  Distance from end of extension case to end of rear drive shaft
    0.45 mm (0.0177 in): Gasket thickness
    l  : Distance from end of transmission case to end of reduction drive gear
    T:  Shim thickness 0.05 - 0.25 mm (0.0020 - 0.0098 in)
    Example: 
    When, L = 90.50 mm (3.5360 in), l  = 90.35 mm (3.5571 in)
    Calculation when clearance is 0.05 mm (0.0020 in)
    H = (90.50 + 0.45) - 90.35 - 0.05 = 0.55
    [H = (3.5630 + 0.0177) - 3.5571 - 0.0020 = 0.0217]
    Calculation when clearance is 0.25 mm (0.0098 in)
    H = (90.50 + 0.45) - 90.35 - 0.25 = 0.35
    [H = (3.5630 + 0.0177) - 3.5571 - 0.0098 = 0.0138]
    After calculation, the value of H becomes between 0.35 mm (0.0138 in) - 0.55 mm (0.0217 in), therefore select either 2 shims of a thickness 0.2 mm (0.010 in) each, or 1 shim 0.5 mm (0.020 in) thick.
    Fig 4: Shims For Adjustment Chart
    G01998967Courtesy of SUBARU OF AMERICA, INC.